AP EAMCET202021 Sep 2020Evening ShiftPhysicsMagnetic Effects of CurrentActual
A proton enters a magnetic field of flux density (1.5 ~Wb ~m ⁻² ) with a velocity of (2 10^7 ~ms ⁻¹ ) at an angle of (30^ ) with the field. The force on the proton will be
Options
- A(2.4 10⁻¹² ~N )
- B(24 10⁻¹² ~N )
- C(0.24 10⁻¹² ~N )
- D(0.024 10⁻¹² ~N )
Correct answer
A. (2.4 10⁻¹² ~N )
Step-by-step solution
Magnetic flux density, (B=1.5 Wbm ⁻² ) Velocity of proton, (v=2 10^7 ~ms ⁻¹ ) ( =30^ ) Charge on proton, (q=1.6 10⁻¹⁹ C ) ( ) Force on the proton, ( aligned F & =B q v & =1.5 1.6 10⁻¹⁹ 2 10^7 30^ & =4.8 10⁻¹² 1 2 =2.4 10⁻¹² ~N aligned )