The magnetic field due to a current carrying loop of radius 3 ~cm at a point on its axis at a distance of 4 ~cm from its centre of 54 T . Then, the value of the magnetic field at the centre of the loop is

Step-by-step solution

B_ axis =54 10⁻⁶= N I r^2 2 (r^2+x^2 )^ 3 / 2 Here, r=3 ~cm =3 10⁻² ~m and x=4 ~cm =4 10⁻² ~m . From above relation, we get N I= 54 10⁻² 2 (25 10⁻⁴ )^ 3 / 2 (3 10⁻² )^2 So, B_ centre = N I 2 r =250 T