Velocity and acceleration vectors of charged particle moving perpendicular to the direction of a magnetic field at a given instant of time are v =2 i +c j and a =3 i +4 j respectively. Then the value of c is

Step-by-step solution

When a charged particle moves perpendicular to the magnetic field, it follows a circular path. On the circular path its velocity and acceleration will be at right angle to each other. Given, v =2 i +c j , a =3 i +4 j As v and a are perpendicular, hence v a =0(2 i +c j ) (3 i +4 j )=0 6+4 c=0 c=-1.5