AP EAMCET2007PhysicsMagnetic Effects of Current
An electron beam travels with a velocity of 1.6 10^7 ~ms ⁻¹ perpendicularly to magnetic field of intensity 0.1 ~T . The radius of the path of the electron beam (m_e=9 10⁻³¹ ~kg . )
Options
- A9 10⁻⁵ ~m
- B9 10⁻² ~m
- C9 10⁻⁴ ~m
- D9 10⁻³ ~m
Correct answer
C. 9 10⁻⁴ ~m
Step-by-step solution
In a perpendicular magnetic field, the radius of circular path travelled by electron beam is aligned r & = m v e B r & = 9 10⁻³¹ 1.6 10^7 1.6 10⁻¹⁹ 0.1 & =9 10⁻⁴ ~m aligned