AP EAMCET2005PhysicsMagnetic Effects of Current
A particle of mass 1 10⁻²⁶ ~kg and charge 1.6 10⁻¹⁹ C travelling with a velocity 1.28 10^6 ~ms ⁻¹ along the positive X -axis enters a region in which a uniform electric field E and a uniform magnetic field of induction B are present. If E =-102.4 10^3 k NC ⁻¹ and B =8 10⁻² j Wbm ⁻² the direction of motion of the particles is
Options
- Aalong the positive X -axis
- Balong the negative X -axis
- Cat 45^ to the positive X -axis
- Dat 135^ to the positive X -axis
Correct answer
A. along the positive X -axis
Step-by-step solution
aligned m & =1 10⁻²⁶ ~kg , q=1.6 10⁻¹⁹ C v & =1.28 10^6 ~m / s aligned Electric field, E =-102.4 10^3 k N / C Magnetic field, B =8 10⁻² j Wbm ⁻² aligned | E | | B | & = 102.4 10^3 8 10⁻² & = 10.24 10^6 8 & =1.28 10^6 aligned Hence, | v |= | E | | B | So, particle will remain undeflected, hence direction of motion of particle is along the positive X -axis.