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AP EAMCET2005PhysicsMagnetic Effects of Current

A particle of mass 1 10⁻²⁶ ~kg and charge 1.6 10⁻¹⁹ C travelling with a velocity 1.28 10^6 ~ms ⁻¹ along the positive X -axis enters a region in which a uniform electric field E and a uniform magnetic field of induction B are present. If E =-102.4 10^3 k NC ⁻¹ and B =8 10⁻² j Wbm ⁻² the direction of motion of the particles is

Options

  1. Aalong the positive X -axis
  2. Balong the negative X -axis
  3. Cat 45^ to the positive X -axis
  4. Dat 135^ to the positive X -axis

Correct answer

A. along the positive X -axis

Step-by-step solution

aligned m & =1 10⁻²⁶ ~kg , q=1.6 10⁻¹⁹ C v & =1.28 10^6 ~m / s aligned Electric field, E =-102.4 10^3 k N / C Magnetic field, B =8 10⁻² j Wbm ⁻² aligned | E | | B | & = 102.4 10^3 8 10⁻² & = 10.24 10^6 8 & =1.28 10^6 aligned Hence, | v |= | E | | B | So, particle will remain undeflected, hence direction of motion of particle is along the positive X -axis.

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