A proton of velocity a (3 i +2 j ) ms ⁻¹ enters field of magnetic induction (2 j +3 k ) tesla, the acceleration produced in the proton in ms ⁻² is ( . Specific charge of proton =0.96 10^8 Ckg ⁻¹ )

Step-by-step solution

V =(3 i +2 j ) m / s , B =(2 j +3 k ) T Specific charge e m =0.96 10^8 Ckg ⁻¹ Force acting on the proton F =q( V B ) aligned V B & = | array ccc i & j & k 3 & 2 & 0 0 & 2 & 3 array | & =6 i -9 j +6 k F & =q(6 i -9 j +6 k ) aligned From Newton's law F = ma m a =q(6 i -9 j +6 k ) aligned Acceleration a & = q m (6 i -9 j +6 k ) & = e m (6 i -9 j +6 k ) & =0.96 10^8 3(2 i -3 j +2 k ) & =288 10^8(2 i -3 j +2 k ) aligned