AP EAMCET2001PhysicsMagnetic Effects of Current
A particle of mass 0.6 ~g and having charge of 25 nC is moving horizontally with a uniform velocity 1.2 10^4 ~ms ⁻¹ in a uniform magnetic field, then the value of the magnetic induction is (g=10 ~ms ⁻² )
Options
- Azero
- B10 ~T
- C20 ~T
- D200 ~T
Correct answer
C. 20 ~T
Step-by-step solution
gathered m=0.6 ~g =0.6 10⁻³ ~kg , q=25 nC =25 10⁻⁹ C v=1.2 10^4 ~m / s gathered The particle is moving with uniform velocity (acceleration is zero), so magnetic force will be balancing the weight of the particle. m g=B q v aligned 0.6 10⁻³ 10 & =B 25 10⁻⁹ 1.2 10^4 B & = 0.6 10⁻³ 10 25 10⁻⁹ 1.2 10^4 & = 6 10⁻³ 30 10⁻⁵ = 6 10^2 30 & =20 ~T aligned