A force F 1 → of magnitude 4 N acts on an object of mass 1 kg at origin in a direction 30 ° above the positive x - axis. A second force F 2 → of magnitude 4 N acts on the same object in the direction of the positive y - axis. The magnitude of the acceleration of the object is nearly

Step-by-step solution

Using parallelogram law of vector addition, Resultant force acting on object is F R = F 1 2 + F 2 2 + 2 F 1 F 2 cos θ , here, θ = 90 ° - 30 ° = 60 ° is angle between the forces. Putting the values, we have F R = 4 2 + 4 2 + 2 4 4 cos 60 ° = 6 . 9   N Acceleration of the object is a = F R m = 6 . 9 1 = 6 . 9   m   s - 2 .