AP EAMCET201921 Apr 2019Morning ShiftPhysicsMathematics in PhysicsActual
Two intervals of time are measured as t₁=(2.00 0.02) s and t₂=(4.00 0.02) s . The value of ( t₁ ) ( t₂ ) with correct significant figures and error is
Options
- A(2.828 0.01) s
- B(2.83 0.01) s
- C(2.828 0.0075) s
- D(2.83 0.0075) s
Correct answer
B. (2.83 0.01) s
Step-by-step solution
Here, t₁=(2.00 0.02) s and t₂=(4.00 0.02) s Given, T= ( t₁ ) ( t₂ ) = (2.00)(4.00) =2.828427 ~s Now, according to the relative error of product T T = ( 1 2 t₁ t₁ + 1 2 t₂ t₂ ) Since, t₁ and t₂ have 3 significant figures, then T also has 3 significant figures. Hence, after rounding off, array rlrl & & T & =2.83 ~s & Now, & T & = 1 2 ( 0.02 2.00 + 0.02 4.00 ) 2.8284 T & =0.02121 ~s array So, after rounding off, aligned T & =0.02 T & =(2.83 0.02) s aligned Hence, So, most matched answer is (b).