Water is flowing in streamline manner in a horizontal pipe. If the pressure at a point where cross-sectional area is 10 ~cm ^2 and velocity 1 ~ms ⁻¹ is 2000 Pa , then the pressure of water at another point where the cross-sectional area 5 ~cm ^2 is

Step-by-step solution

By equation of continuity aligned & A₁ V₁=A₂ V₂ & 10 1=5 v₂ v₂=2 ~m / s aligned Applying Bernoulli's theorem at point 1 and 2 , aligned & P ₁= 1 2 v ₁^2= P ₂+ 1 2 v ₂^2 & 2000+ 1 2 10^3 1^2= P ₂+ 1 2 10^3 2^2 & P ₂=2000+ 1 2 10^3 (1^2-2^2 ) & =500 ~Pa aligned