AP EAMCET202420 May 2024Evening ShiftPhysicsMechanical Properties of FluidsActual
Two mercury drops, each with same radius r , merged to form a bigger drop. T is the surface tension of mercury, then the surface energy of bigger drop is given by
Options
- A2 r^2 ~T
- B2^ 5 / 3 r^2 ~T
- C2 r^2 ~T ^2
- D2^ 8 / 3 r^2 ~T
Correct answer
D. 2^ 8 / 3 r^2 ~T
Step-by-step solution
V _ i = V _ f 2 4 3 r ^3= 4 3 R ^3 R =(2)^ 1 3 r Surface energy of bigger drop, aligned & E = TA = T (4 R ^2 )=4 (2)^ 2 / 3 r ^2 ~T & =2^ 8 / 3 r ^2 ~T aligned