AP EAMCET20227 Jul 2022Morning ShiftPhysicsMechanical Properties of FluidsActual
A large tank open to atmosphere at top and filled with water, develops a small hole in the side at a point 20 ~m below the water level. If the rate of flow of water from the hole is 3 10⁻³ ~m ^3 / min then the area of hole is (Acceleration due to gravity =10 ~ms ⁻² )
Options
- A4 ~mm ^2
- B1.5 ~mm ^2
- C2.5 ~mm ^2
- D2 ~mm ^2
Correct answer
C. 2.5 ~mm ^2
Step-by-step solution
As we know that, rate of flow through a hole = Velocity of efflux Area of hole. V t =v A V t = 2 g h A ...(i) ( v= 2 g h ) Here, h=20 ~m A= ? Rated of flow of water, V t =3 10⁻³ ~m ^3 / min = 3 60 10⁻³ ~m / s Substituting values in Eq. (i), we get 3 60 10⁻³= 2 10 20 A A= 3 10⁻³ 60 2 10 20 =25 10⁻⁶ ~m ^2=2.5 ~mm ^2