A block of wood of volume V floats in water with half of its volume submerged. The same block floats in an oil with 0.8 ~V volume submerged. If the density of water is 1000 ~kg ~m ⁻³ , then the density of the oil is

Step-by-step solution

Given, density of water, _w=1000 kgm ⁻³ For the block of wood in water, volume of immersed part Total volume of block of wood aligned & = Density of wood ( _s ) density of water ( _w ) V V & = _s 1000 1 2 = _s 1000 _s & =500 kgm ⁻³ aligned Similarly, for the block of wood in oil aligned 0.8 ~V V & = _s _ oil _ oil & = _s 0.8 = 500 0.8 & =625 kgm ⁻³ aligned