AP EAMCET20225 Jul 2022Evening ShiftPhysicsMechanical Properties of FluidsActual
Energy needed in breaking a liquid drop of radius R , into n smaller drops each of radius r , is [T- Surface tension of the liquid]
Options
- A(4 r^2 n-4 R^2 ) T
- B( 4 3 r^3 n- 4 3 R^3 ) T
- C(4 R^2-4 r^2 ) n T
- D(4 R^2-n 4 r^2 ) / T
Correct answer
A. (4 r^2 n-4 R^2 ) T
Step-by-step solution
We have U = (surface energy of bigger drop) - (surface energy of lower drop) aligned & U = ( T 4 R ^2 )- ( nT 4 r ^2 ) & | U |= (4 r ^2 n -4 R ^2 ) T aligned