AP EAMCET202422 May 2024Evening ShiftPhysicsMechanical Properties of SolidsActual
A wire of length 100 cm and area of cross-section 2 ~mm ^2 is stretched by two forces of each 440 N applied at the ends of the wire in opposite directions along the length of the wire. If the elongation of the wire is 2 mm , the Young's modulus of the material of the wire is
Options
- A4.4 10¹¹ Nm ⁻²
- B1.1 10¹¹ Nm ⁻²
- C2.2 10¹¹ Nm ⁻²
- D3.3 10¹¹ Nm ⁻²
Correct answer
B. 1.1 10¹¹ Nm ⁻²
Step-by-step solution
1=100 ~cm =100 10⁻² ~m , ~A =2 ~mm ^2=2 10⁻⁶ ~m ^2 F =440 ~N , l =2 ~mm =2 10⁻³ ~m Young's modulus of the wire is Y = Fl ~A . l = 440 100 10⁻² 2 10⁻⁶ 2 10⁻³ =1.1 10¹¹ Nm ⁻²