A 4 kg stone attached at the end of a steel wire is being whirled at a constant speed 12 ~ms ⁻¹ in a horizontal circle. The wire is 4 m long with a diameter 2.0 mm and young's modules of the steel is 2 10¹¹ Nm ⁻² . The strain in the wire is.

Step-by-step solution

M =4 ~kg , v =12 ~m / s , l =4 ~m , ~d =2 ~mm =2 10⁻³ ~m Y =2 10¹¹ Nm ⁻² Force developed in the wire, F= m v^2 1 = 4 12 12 4 =144 N The strain produced in the wire is aligned & E = F AY = 4 ~F ~d ^2 Y = 4 144 (2 10⁻³ )^2 2 10¹¹ & =2.3 10⁻⁴ aligned