AP EAMCET202021 Sep 2020Morning ShiftPhysicsMechanical Properties of SolidsActual
If a pressure of (8 10^8 ~N ~m ⁻² ) is applied to a lead block, so that its volume reduces by (20 % ). The Bulk modulus of lead block is
Options
- A(4 10^7 Nm ⁻² )
- B(4 10^8 Nm ⁻² )
- C(4 10^9 Nm ⁻² )
- D(4 10¹⁰ Nm ⁻² )
Correct answer
C. (4 10^9 Nm ⁻² )
Step-by-step solution
Pressure applied on the block, (p=8 10^8 Nm ⁻² ) If (V₁ ) be initial volume, then final volume of block, ( aligned & V₂=V₁-20 % of V₁=V₁- 20 100 V₁ & V₂= 4 5 V₁ aligned ) ( ) Change in volume, ( V=V₁-V₂=V₁- 4 5 V₁ = V₁ 5 ) ( ) Bulk modulus, ( aligned B & = p V / V = p V V = 8 10^8 V₁ V₁ / 5 & =4 10^9 Nm ⁻² aligned )