AP EAMCET202316 May 2023Morning ShiftPhysicsMotion in One DimensionActual
A car moving with uniform acceleration covers the distance of 200 ~m in first 2 seconds and the distance of 220 ~m in next 4 seconds. The velocity of the car after 7 seconds is
Options
- A10 ~ms ⁻¹
- B20 ~ms ⁻¹
- C15 ~ms ⁻¹
- D30 ~ms ⁻¹
Correct answer
A. 10 ~ms ⁻¹
Step-by-step solution
Distance travelled in first 2 seconds =200 ~m S=u t+ 1 2 a t^2200=2 u+ 1 2 a 2^2u+a=100 ...(1) Distance travelled in next 4 seconds =220 ~m Total distance travelled in first 6 second =420 ~m aligned & 420=6 u+ 1 2 9 6^2 & 420=6 u+18 a aligned u +3 a =70 ...(2) Solving equation (1) and (2), we have aligned & a =-15 ~m / s ^2, u =115 ~m / s & v = u + at & =115-15 7 & =115-105=10 ~m / s aligned