AP EAMCET20225 Jul 2022Evening ShiftPhysicsMotion in One DimensionActual
At the moment t =0 , a time dependent force F = at (where a is constant equal to 1 Ns ⁻¹ ) is applied to a body of mass 1 ~kg resting on a smooth horizontal plane as shown in the figure. If the direction of this force makes an angle 45^ with the horizontal, then the velocity of the body at the moment it leaves the plane is (acceleration due to gravity =10 ~m ~s ⁻² )
Options
- A50 ~ms ⁻¹
- B50 2 ~ms ⁻¹
- C100 2 ~ms ⁻¹
- D100 ~ms ⁻¹
Correct answer
B. 50 2 ~ms ⁻¹
Step-by-step solution
When body left the surface, N =0 So, m g= at 45^ t = mg a 45^ = 10 1.1 2 =10 2 sec Now, a = dv dt dv = adt aligned & ₀^ v dv = at 45^ dt v = a 2 [ t ^2 2 ]₀^ 10 2 & v = a 2 1 2 [200-0] & v =50 2 ~m / s aligned