AP EAMCET202023 Sep 2020Morning ShiftPhysicsMotion in One DimensionActual
The acceleration at the end of 2 s , of a particle whose motion is represented by the equation S = 4 t 3 - 8 t 2 + 5 t + 4 is ______
Options
- A32   m   s - 2
- B40   m   s - 2
- C37   m   s - 2
- D35   m   s - 2
Correct answer
A. 32   m   s - 2
Step-by-step solution
Given that displacement S = 4 t 3 - 8 t 2 + 5 t + 4 velocity v = d S d t ⇒ v = d 4 t 3 - 8 t 2 + 5 t + 4 d t ⇒ v = 12 t 2 - 16 t + 5 acceleration a = d v d t ⇒ a = d 12 t 2 - 16 t + 5 d t ⇒ a = 24 t - 16 so acceleration at t = 2   a = 24 2 - 16 = 32   m   s - 2