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AP EAMCET201825 Apr 2018Morning ShiftPhysicsMotion in One DimensionActual

A body is projected vertically upwards with a velocity ' u ' from the top of a tower. Time taken by it to reach the ground is ' n ' times the time taken by it to reach the highest point in its path. Height of the tower is

Options

  1. An u 2 ( n - 1 ) 2 g
  2. Bn u 2 ( n - 2 ) g
  3. Cn u 2 ( n - 2 ) 2   g
  4. Du 2 2 g ( n + 1 )

Correct answer

C. n u 2 ( n - 2 ) 2   g

Step-by-step solution

Let us suppose. h is the height of the tower and it attains maximum height up to H from ground, so Time to reach the maximum height, t = u g if t 2 is the time taken by the ball to hit the ground, - H = u t 2 - 1 2 g t 2 2 t 2 = n t - H = u n t - 1 2 g n t 2 ⇒ - H = u n u g - 1 2 g n × u g 2 ⇒ H = n u 2 n - 2 2 g

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