AP EAMCET201824 Apr 2018Morning ShiftPhysicsMotion in One DimensionActual
The motion of a particle along a straight line is described by the function, x=(2 t-3)^2 where x is in metres and t is in seconds. The acceleration of the particle at t=2 ~s is
Options
- A1 ~ms ⁻²
- B4 ~ms ⁻²
- C8 ~ms ⁻²
- D7 ~ms ⁻²
Correct answer
C. 8 ~ms ⁻²
Step-by-step solution
Given, x=(2 t-3)^2 where, aligned & x= displacement and t= time. & x=4 t^2+9-12 t aligned Differentiate w.r.t. time, we get Velocity, v= d x d t =8 t-12 Acceleration, a= d v d t =8 ~m / s ^2