AP EAMCET201726 Apr 2017Morning ShiftPhysicsMotion in One DimensionActual
A person of 60 ~kg mass is in a lift which is coming down such that the man exerts a force of 150 ~N on the floor of the lift. Then the acceleration of the lift is (g=10 ~ms ⁻² )
Options
- A7.5 ~ms ⁻²
- B40.0 ~ms ⁻²
- C22.5 ~ms ⁻²
- D15.0 ~ms ⁻²
Correct answer
A. 7.5 ~ms ⁻²
Step-by-step solution
Here g_ e f f =g-a So, m(g-a)=150 ~N 60(10-a)=150a=7.5 ~m / s ^2