AP EAMCET2014PhysicsMotion in One Dimension
A bus moving on a level road with a velocity v can be stopped at a distance of x , by the application of a retarding force F . The load on the bus is increased by 25 % by boarding the passengers. Now, if the bus is moving with the same speed and if the same retarding force is applied, the distance travelled by the bus before it stops is
Options
- A1.25 x
- Bx
- C5 x
- D2.5 x
Correct answer
A. 1.25 x
Step-by-step solution
By third's law of motion v^2=u^2+2 a s aligned v^2-u^2 & =-2 ( F m ) s -u^2 & =-2 F m s u^2 & = 2 F s m or m & = 2 F s u^2 m s aligned Given s₁=x aligned s₂ & =? m₁ & =m m₂ & =m 25 %+m aligned Now, m₁ m₂ = s₁ s₂ aligned m m 25 100 +m & = x s₂ s₂ & = x m ( 100+25 100 ) m s₂ & = 125 100 x s₂ & =1.25 x aligned