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AP EAMCET202421 May 2024Morning ShiftPhysicsMotion in Two DimensionsActual

An object projected upwards from the foot of a tower. The object crosses the top of the tower twice with an interval of 8 s and the object reaches foot after 16 s . The height of the tower is [ g =10 ~ms ⁻² ]

Options

  1. A220 m
  2. B240 m
  3. C640 m
  4. D80 m

Correct answer

B. 240 m

Step-by-step solution

During downwârd journey, aligned & t _ BC = 8 2 =4 ~s & t _ AC = 16 2 =8 ~s aligned Height of the tower is H = 1 2 g ( t _ AC ^2- t _ BC ^2 )= 1 2 10 (8^2-4^2 )=240

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