A projectile is launched from the ground, such that it hits a target on the ground which is 90 ~m away. The minimum velocity of projectile to hit the target is (acceleration due to gravity =10 ~ms ⁻² )

Step-by-step solution

Since, launched projectile hit the target on the ground 90 ~m away hence, range, R=90 ~m . For minimum velocity (u_ ) of projectile, range should be maximum. i.e. =45^ R= u^2 2 g array ll & 90= u_ ^2 2 45^ 10 900=u_ ^2 & u_ = 900 =30 ~m / s array