A hiker stands on the edge of a cliff 490 m above the ground and throws a stone horizontally with an initial speed of 15 m s - 1 . The speed with which it hits the ground is

Step-by-step solution

From the equation of kinematics, v 2 - u 2 = 2 g h There is no opposing force in the horizontal direction, ⇒ v x = 15   m   s - 1 In vertical direction, v y 2 = 2 g h ⇒ v y 2 = 2 × 9 . 8 × 490 ⇒ v y = 2 × 9 . 8 × 490 ⇒ v y = 2 × 9 . 8 × 490 ⇒ v y = 98   m   s - 1 Final velocity, v = v x 2 + v y 2 ⇒ v = 15 2 + 98 2 ⇒ v = 99   m   s - 1