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AP EAMCET202120 Aug 2021Morning ShiftPhysicsMotion in Two DimensionsActual

The range of a projectile is 100 m . Its kinetic energy will be maximum after covering a distance of:

Options

  1. A25   m
  2. B50   m
  3. C75   m
  4. D100   m

Correct answer

D. 100   m

Step-by-step solution

The expression for a horizontal range of a projectile is, R = u 2 sin 2 θ g   here, θ   is the angle of projection and u   is the initial resultant velocity. The expression for kinetic energy is, K E = 1 2 m v 2 For the maximum kinetic energy, the velocity should be maximum, now the velocity of the projectile is u = u x 2 + u y 2 In the expression of the velocity of particle during projectile, the horizontal component of velocity is constant, i.e., u x = constant   therefore, net veloc

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