When a ball is thrown with a velocity of 50 m s - 1 at an angle 30 ° with the horizontal, it remains in the air for seconds. (take g = 10 m s - 2

Step-by-step solution

The vertical component of velocity is, 50 sin 30 °   therefore, u = 50 sin 30 °   and when the ball will be thrown vertically the net displacement along the vertical direction of body will be zero, since body will again come to ground after time t . Now using the equation of uniform motion, s = u t + 1 2 a t 2 ⇒ 0 = 50 sin 30 ° t + 1 2 - g t 2 ⇒ 5 t 2 - 50 sin 30 ° t = 0                     ⋯ ⋯ g = 10   m &#