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AP EAMCET201923 Apr 2019Morning ShiftPhysicsMotion in Two DimensionsActual

A body is projected at an angle of (45^ ) from a point on the ground at a distance of (30 ~m ) from the foot of a vertical pole of height (20 ~m ). The body just crosses the top of the pole and strikes the ground at a distance (s ) from the foot of the pole on the other side of the pole. Then, (s )

Options

  1. A(20 ~m )
  2. B(30 ~m )
  3. C(50 ~m )
  4. D(60 ~m )

Correct answer

D. (60 ~m )

Step-by-step solution

According to the question, projection of a body shown in the figure below, Now, from the above figure, let (t ) be the time of crossing of pole, then, (30=t u 45^ ) ...(i) and (20=u 45^ t- 10 2 t^2 ) ...(ii) Hence, (30 2 =u t ) and ( array ll & 20= u 2 t-5 t^2 & t= 2 ~s and u=30 ~m / s Hence, R= & u^2 2 g = 30 30 90^ 10 =90 ~m array ) ( ) Distance between pole and the point at which body strike on the ground, ( s=(90-30)=60 ~m ) So, the correct option is (d).

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