If the maximum height and range of a projectile are 3 ~m and 4 ~m respectively, then the velocity of the projectile is (Take, g=10 ~ms ⁻² )

Step-by-step solution

Here, maximum height, H=3 ~m and range, R=4 ~m As, maximum height, H= u^2 ^2 2 g and maximum range, R= u^2 2 g The ratio, array rlrl & & H R & = 3 4 = ^2 2 2 3 2 =2 ^2 & & =3 ( 2 =2 ) array From Eqs. (i) and (ii), we get aligned & 3 2 10=u^2 ^2 3 2 10=u^2 ( 3 10 )^2 & u^2= ( 10 3 )^2 3 2 10 u^2= 100 2 3 u=10 2 3 aligned Hence, the correct option is (c).