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AP EAMCET201920 Apr 2019Morning ShiftPhysicsMotion in Two DimensionsActual

A gun and a target are at the same horizontal level separated by a distance of (600 ~m ). The bullet is fired from the gun with a velocity of (500 ~ms ⁻¹ ). In order to hit the target, the gun should be aimed to a height (h ) above the target. The value of (h ) is (Acceleration due to gravity, (g=10 ~ms ⁻² ) )

Options

  1. A(2.4 ~m )
  2. B(3.6 ~m )
  3. C(7.2 ~m )
  4. D(10.8 ~m )

Correct answer

C. (7.2 ~m )

Step-by-step solution

Given, distance between gun and target (=600 ~m ) velocity of bullet (=500 ~ms ⁻¹ ) Now, distance (= ) velocity of bullet ( ) time ( gathered 600=500 t t= 600 500 = 6 5 =1.2 sec gathered ) From second equation of the motion, (h=u t+ 1 2 g t^2 ) Putting the given values, we get ( aligned h & =0 (1.2)+ 1 2 (-10) (1.2)^2 h & = 1 2 (-10)(1.2 1.2) h & =-7.2 ~m |h| & =7.2 ~m aligned )

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