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AP EAMCET201825 Apr 2018Morning ShiftPhysicsMotion in Two DimensionsActual

Two towers A and B , each of height 20 m are situated a distance 200 m apart. A body thrown horizontally from the top of the tower A with a velocity 20 ms - 1 towards the tower B hits the ground at point P and another body thrown horizontally from the top of tower B with a velocity 30 ms - 1 towards the tower A hits the ground at point Q . If a car starting from rest from P reaches Q in 10 seconds, the acceleration o

Options

  1. A1   ms - 2
  2. B2   ms - 2
  3. C3   ms - 2
  4. D4   ms - 2

Correct answer

B. 2   ms - 2

Step-by-step solution

The time taken by both the ball to reach the ground is same because initial vertical velocity and height of the tower is the same in each case, A P = 20 × 2 h g = 20 × 40 10 = 40   m Q B = 20 × 2 h g = 30 × 40 10 = 60   m P Q = 200 - 100 = u t + 1 2 a t 2 = 0 + 1 2 × a 100 100 = 50 a a = 2   m   s - 2

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