A body projected with some velocity at an angle 45^ with the horizontal from the origin in X Y -plane passes through a point at (4,3) m . Its horizontal range is

Step-by-step solution

Equation of trajectory of projectile is y=x - g x^2 2 u^2 ^2 Here, =45^ array rlrl When & y & =3, x=4, so 3=4- g (4^2 ) u^2 & & 16 g u^2 & =1 & & u^2 & =16 g array Substituting the value of u^2 in Eq (i), we get aligned & y=x- g x^2 16 g & y=x- x^2 16 aligned How at maximum x, y=0 . Hence, x- x^2 16 =0 x (1- x 16 )=0 x=0 (initial position) and x=16 ~m (final position).