AP EAMCET2002PhysicsMotion in Two Dimensions
The horizontal and vertical displacements of a projectile at time t are x=36 t and y=48 t-4.9 t^2 , respectively. Initial velocity of the projectile in m / s is
Options
- A15
- B30
- C45
- D60
Correct answer
D. 60
Step-by-step solution
x=36 t y=48 t-4.9 t^2 Comparing with x=u t y=u t- 1 2 g t^2 where, u= initial velocity aligned & u =36, & u =48 aligned aligned (u )^2+(u )^2 & =36^2+48^2 u^2 ( ^2 + ^2 ) & =3600 u^2 & =3600 u & =60 ~m / s aligned