Quantrex Quantrex AcademyJEE · NEET · NDA PYQs with solutions Open app
AP EAMCET2001PhysicsMotion in Two Dimensions

An object is projected with a velocity of 20 ~m / s making an angle of 45^ with horizontal. The equation for the trajectory is h=A x-B x^2 where h is height, x is horizontal distance A and B are constants. The ratio A: B is (g=10 ~ms ⁻² )

Options

  1. A1: 5
  2. B5: 1
  3. C1: 40
  4. D40: 1

Correct answer

D. 40: 1

Step-by-step solution

u=20 ~m / s , =45^ Equation of trajectory h=A x-B x^2 Standard equation h=x - g x^2 2 u^2 ^2 On comparing the two equations aligned A & = , B= g 2 u^2 ^2 A B & = g 2 u^2 ^2 = 2 u^2 ^2 g & = 2 (20)^2 ^2 45^ 45^ 10 & = 2 400 ( 1 2 )^2 1 10 & =2 40 1 2 =40 aligned A: B=40: 1

Practice Motion in Two Dimensions on Quantrex Academy →

More from Motion in Two Dimensions

A boy, standing at a certain height, kicks a football horizontally with a velocity of 19.6 ms⁻¹ . What will be the ratio of horizontal and vertical components of velocities after 2 2026From the same point, two stones A and B are thrown simultaneously, A is thrown up vertically with a velocity of 10 ms⁻¹ and B is thrown up with the same velocity at 30^ with the ho 2026Two bodies are projected with the same velocity. If one is projected at an angle of 30^ and the other at 45^ to the horizontal, then the ratio of maximum heights attained is 2026If two bodies A and B are projected with same velocity but with different angles ₁ and ₂ respectively with the horizontal such that both will have same range, then the ratio of tim 2025If the horizontal range of a body projected with a velocity ' u ' is 3 times the maximum height reached by it, then the range of the body is (g - acceleration due to gravity) 2025If the velocity at the maximum height of a projectile projected at an angle of 45^ is 20 ~m ~s ⁻¹ , then the maximum height reached by the projectile is (Acceleration due to gravit 2025If the range of a body projected with a velocity of 60 ~m ~s ⁻¹ is 180 3 ~m , then the angle of projection of the body is (Acceleration due to gravity =10 ~m ~s ⁻² ) 2025If the height of a projectile at a time of 2 s from the beginning of motion is 60 m, then the time of flight of the projectile is (Acceleration due to gravity =10 ~m ~s ⁻² ) 2025 Full Motion in Two Dimensions list All AP EAMCET PYQs