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AP EAMCET202124 Aug 2021Evening ShiftPhysicsSemiconductorsActual

If current in diode is five times that in R₁ and breakdown voltage of diode is 6 ~V , find the value of R ?

Options

  1. A2000
  2. B2000 3
  3. C1000
  4. D1000 3

Correct answer

B. 2000 3

Step-by-step solution

Given that, R_ l =1 k , Zener breakdown voltage V_z=6 ~V Let I₁ and I_z be the current passing through R₁ and Zener diode, then using equation, I₁= V_z R₁ = 6 1000 ~A According to given condition Zener current, I_z=5 I₁= 30 1000 ~A Let I be the current drawn from source battery (V_s=30 ~V ) , then I= V_ s -V_z R =I₁+I_z 30-6 R = 6 1000 + 30 1000 R= 2000 3

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