AP EAMCET202017 Sep 2020Evening ShiftPhysicsSemiconductorsActual
In a (p ) - (n-p ) transistor working as a common base amplifier, when the current gain is 0.96 and emitter current is (7.2 ~mA ), the base current is
Options
- A(0.4 ~mA )
- B(0.2 ~mA )
- C(0.29 ~mA )
- D(0.35 ~mA )
Correct answer
C. (0.29 ~mA )
Step-by-step solution
In common base amplifier for (p-n-p ) transistor, current gain, ( =0.96 ) Emitter current, (I_E=7.2 ~mA ) We know that, ( aligned & & = I_C I_E 0.96= I_C 7.2 & I_C & =0.96 7.2=6.912 ~mA aligned ) ( ) Base current, ( aligned I_B & =I_E-I_C=7.2-6.912 & =0.288 ~mA 0.29 ~mA aligned )