Water of mass m at 30^ C is mixed with 5 g of ice at -20^ C . If the resultant temperature of the mixture is 6^ C , then the value of m is (specific heat capacity of ice g ⁻¹ ^ C ⁻¹ and latent heat of fusion of ice =80 cal g ⁻¹ )

Step-by-step solution

By principle of calorimetry, aligned & Heat lost = Heat gained & m _ w C _ pw ( T _ w - T )= m _ i c _ pi ( o - T _ i )+ m _ i L _ i + m _ i & c _ pw ( T - O ) & m 1 (30-6)=5 0.5(0+20)+5 80+5 1 & (6-0) & m = 50+400+30 24 =20 ~g aligned