A 50 ~g ice cube at -10^ C is added to 200 ~g of water at 30^ C . The final temperature of the mixture is (specific heat of water =1 cal g ⁻¹ ^ C ⁻¹ , latent heat of fusion of ice =80 cal g ⁻¹ specific heat of ice =0.5 cal g ⁻¹ ^ C ⁻¹ )

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Correct answer: B. 7^ C

Mass of ice, m =50 ~g Temperature, T =-10^ C Added mass, m ^ =200 ~g Temperature at which mass added, T ^ =30^ C final temperature of mixture, T _ f = ? Heat lost = heat gained aligned & m ^ C _ w T _ w = mC _ i T _ i + mL ^ L & 200 1 (30- T _ f )=50 0.5 ( T _ f +10 )+50 80 & ~T _ f =7^ C aligned

A 50 ~g ice cube at -10^ C is added to 200 ~g of water at 30^ C . The final temperature of the mixture is (specific heat of water =1 cal g ⁻¹ ^ C ⁻¹ , latent heat of fusion of ice =80 cal g ⁻¹ specific heat of ice =0.5 cal g ⁻¹ ^ C ⁻¹ )

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