When a meter rod made of silver at 0^ C is heated to 100 ^ C , its length increased by 0.19 ~cm . Then, find the coefficient of volume expansion of the silver.

Step-by-step solution

Given that, length of silver rod, L=1 ~m Initial temperature, T₁=0^ C Final temperature, T₂=100^ C Increased in length, L=0.19 ~cm Let and be the coefficient of linear and volume expansions. Then, we know that, L=L T Substituting the values, we get 0.19 100 =1 (T₂-T₁ ) 0.19 100 = (100-0) =0.19 10^ -4 C ⁻¹ We also know that, volume expansion, aligned & =3 =3 0.19 10⁻⁴ & =5.7 10⁻⁵⁰ C ⁻¹ aligned