5 ~g of steam at 100^ C is mixed with 5 ~g of ice at 0^ C . What is the final temperature of the mixture?

Step-by-step solution

Given, mass of steam, m_ =5 ~g Temperature of steam, T_s=100^ C Mass of ice, m_i=5 ~g Temperature of ice, T_i=0^ C Since, latent heat of vaporisation, l_v=540 cal / g Latent heat of fusion, l_f=80 cal / g Now, heat given by steam during fully conversion into water, at 100^ C and Q₁=m_ 540=2700 cal Heat taken by ice to get fully converted into water at 100^ C , aligned Q₂ & =m_i l_f+m_i s T & =5 80+5 1 100 ( s=1, for water ) & =400+500=900 aligned As, Q₂ < Q₁ Temperature of mixture will be 100^ C .