AP EAMCET202021 Sep 2020Morning ShiftPhysicsThermal Properties of MatterActual
The rate of radiation of a black body at (0^ C ) is (E Js ⁻¹ ). The rate of radiation of the black body at (273^ C ) will be
Options
- A(E Js ⁻¹ )
- B(4 E Js ⁻¹ )
- C( E 2 Js ⁻¹ )
- D(16 E Js ⁻¹ )
Correct answer
D. (16 E Js ⁻¹ )
Step-by-step solution
Given, (T₁=0^ C =(0+273) K =273 ~K ) (T₂=273^ C =(273+273) K =546 ~K ) According to Stefan-Boltzmann's law, rate of radiation, ( array ll & E T^4 & E₂ E₁ = ( T₂ T₁ )^4= ( 546 273 )^4=(2)^4=16 & E₂=16 E₁=16 E Js ⁻¹ [ E₁=E Js ⁻¹ ] array )