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AP EAMCET2011PhysicsThermal Properties of Matter

Two slabs A and B of different materials but of the same thickness are joined end to end to form a composite slab. The thermal conductivities of A and B are k₁ and k₂ respectively. A steady temperature difference of 12^ C is maintained across the composite slab. If k₁= k₂ 2 , the temperature difference across slab A is

Options

  1. A4^ C
  2. B6^ C
  3. C8^ C
  4. D10^ C

Correct answer

C. 8^ C

Step-by-step solution

The given situation can be shown as Rate of flow of heat will be equal in both the slabs aligned & & (12-x) K₁ & =K₂(x-0) & & 12-x & =2 x ( K₁= K₂ 2 ) & & x & =4^ C aligned The temperature difference across slab aligned A & =(12-x)=(12-4) & =8^ C aligned

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