The total internal energy of 2 moles of a monotomic gas at a temperature 27^ C is U . The total internal energy of 3 moles of a diatomic gas at a temperature 127^ C is

Step-by-step solution

n ₁=2 moles, T ₁=27^ c =300 ~K For monoatomic gas, f₁=3 U = n ₁ f ₁ RT ₁ 2 = 2 3 R 300 2 =900 R For diatomic gas, f ₂=5 aligned & n ₂=3 moles, T ₂=127^ c =400 ~K & U ^ = n ₂ f ₂ RT ₂ 2 = 3 5 R 400 2 =3000 R & U ^ U = 3000 R 900 R = 10 3 & U^ = 10 U 3 aligned