In a Carnot engine, when the temperatures are T₂=0^ C and T₁=200^ C , its efficiency is ₁ and when the temperatures are T₁=0^ C and T₂=-200^ , its efficiency is ₂ . Then the value ₁ ₂ is

Step-by-step solution

For carnot engine, aligned & At T₁=200^ C , ~T ₂=0^ C & ₁=1- T₂ T₁ =1- 273+0 273+200 = 200 473 & At T₁=0^ c , ~T ₂=-200^ c & ₂=1- T₂ ~T ₁ =1- 273+200 273+0 = 200 273 & ₁ ₂ = 200 473 273 200 =0.58 aligned