The efficiency of a Carnot cycle is 1 6 . By lowering the temperature of sink by 65 K , it increases to 1 3 . The initial and final temperature of the sink are

Step-by-step solution

The efficiency of carnot engine is =1- T₂ T₁ 1 6 =1- T₂ T₁ T₂= 5 6 T₁ ....(i) Again, 1 3 =1- T₂-65 T₁ T₂-65 T₁ = 2 3 ....(ii) From eq(i) and (ii), we get 5 T₁ 6 -65= 2 T₁ 3 T₁=390 ~K Initial temperature of sink, T ₂= 5 6 ~T ₁= 5 6 390=325 ~K Final temperature of k , T ₂-65=(325-65)=260 K .