A diatomic gas has an initial internal energy of 80 cal . A work of 18 cal is done on the gas and the gas releases heat energy of 42 ~J . The final internal energy of the gas is

Step-by-step solution

Initial internal energy, U _ i =80 cal =80 4.2 ~J Work done, W =18 cal =18 4.2 ~J Heat released, Q=42 ~J Final internal energy, U _ f = ? using 1st law of thermodynamics aligned & Q= U+ W & Q=U_i-U_f+ W & 42=336-U_f+75.6 & U_f=369.6 J aligned