The temperature of the sink of a Carnot's engine is 300 ~K and the efficiency of the engine is 0.25 . If the temperature of the source of the engine is increased by 100 ~K , the efficiency of the engine increases by

Step-by-step solution

Temperature of the sink, T₂=300 ~K Efficiency of the engine, =0.25 aligned & ₁=1- T ₂ ~T ₁ 0.25=1- 300 ~T ₁ & 300 ~T ₁ =0.75 T ₁= 300 0.75 =400 ~K & ₂=1- T ₂ ~T ₁ =1- 300 400+100 & =1- 300 500 = 2 5 & =0.40 aligned The increase in efficiency, = ₂- ₁=0.40-0.25=0.15