2 moles of a monatomic gas requires heat energy Q to be heated from 30^ C to 40^ C at constant volume. The heat energy required to raise the temperature of 4 moles of a diatomic gas from 28^ C to 33^ C at constant volume is

Step-by-step solution

Heat energy, Q at constant volume, Q = nC _ v T for monatomic gas C _ v = 3 2 R and for diatomic gas, C _ v = 5 2 R aligned & Q =2 3 2 R 10 and Q ^ =4 5 2 R 5 & Q ^ Q = 4 5 2 R 5 2 3 2 R 10 = 5 3 Q ^ = 5 3 Q aligned